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Question

The values of $\alpha$, for which $\left|\begin{array}{ccc}1 & \frac{3}{2} & \alpha+\frac{3}{2} \\ 1 & \frac{1}{3} & \alpha+\frac{1}{3} \\ 2 \alpha+3 & 3 \alpha+1 & 0\end{array}\right|=0$, lie in the interval

$(-2,1)$
$\left(-\frac{3}{2}, \frac{3}{2}\right)$
$(-3,0)$
$(0,3)$

Solution

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