A ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle $(\theta)$ of thread deflection in the extreme position will be :

Question

$\tan ^{-1}\left(\frac{1}{2}\right)$

$2 \tan ^{-1}\left(\frac{1}{2}\right)$

$2 \tan ^{-1}\left(\frac{1}{\sqrt{5}}\right)$

$\tan ^{-1}(\sqrt{2})$

Solution

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