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Question

A heavy iron bar of weight $12 \mathrm{~kg}$ is having its one end on the ground and the other on the shoulder of a man. The rod makes an angle $60^{\circ}$ with the horizontal, the weight experienced by the man is :

$3 \mathrm{~kg}$
$6 \mathrm{~kg}$
$6 \sqrt{3} \mathrm{~kg}$
$12 \mathrm{~kg}$

Solution

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