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Question

Wheatstone bridge principle is used to measure the specific resistance $\left(S_1\right)$ of given wire, having length $L$, radius $r$. If $X$ is the resistance of wire, then specific resistance is ; $S_1=X\left(\frac{\pi r^2}{L}\right)$. If the length of the wire gets doubled then the value of specific resistance will be :

$\frac{S_1}{4}$
$2 \mathrm{~S}_1$
$\frac{\mathrm{S}_1}{2}$
$S_1$

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