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Question

Position of an ant ($\mathrm{S}$ in metres) moving in $\mathrm{Y}$-$\mathrm{Z}$ plane is given by $S=2 t^2 \hat{j}+5 \hat{k}$ (where $t$ is in second). The magnitude and direction of velocity of the ant at $\mathrm{t}=1 \mathrm{~s}$ will be :

$16 \mathrm{~m} / \mathrm{s}$ in $y$-direction
$4 \mathrm{~m} / \mathrm{s}$ in $x$-direction
$9 \mathrm{~m} / \mathrm{s}$ in $\mathrm{z}$-direction
$4 \mathrm{~m} / \mathrm{s}$ in $y$-direction

Solution

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