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Question

If the refractive index of the material of a prism is $\cot \left(\frac{A}{2}\right)$, where $A$ is the angle of prism then the angle of minimum deviation will be

$\pi-2 \mathrm{~A}$
$\frac{\pi}{2}-2 \mathrm{~A}$
$\pi-\mathrm{A}$
$\frac{\pi}{2}-\mathrm{A}$

Solution

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