The position of a particle related to time is given by $x=\left(5 t^{2}-4 t+5\right) \mathrm{m}$. The magnitude of velocity of the particle at $t=2 s$ will be :
$14 \mathrm{~ms}^{-1}$
$16 \mathrm{~ms}^{-1}$
$10 \mathrm{~ms}^{-1}$
$06 \mathrm{~ms}^{-1}$
Solution
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