The de Broglie wavelength of an electron having kinetic energy $\mathrm{E}$ is $\lambda$. If the kinetic energy of electron becomes $\frac{E}{4}$, then its de-Broglie wavelength will be :
$\sqrt{2} \lambda$
$2 \lambda$
$\frac{\lambda}{2}$
$\frac{\lambda}{\sqrt{2}}$
Solution
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