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Question
Two identical particles each of mass ' $m$ ' go round a circle of radius $a$ under the action of their mutual gravitational attraction. The angular speed of each particle will be :
$\sqrt{\frac{G m}{2 a^{3}}}$
$\sqrt{\frac{G m}{a^{3}}}$
$\sqrt{\frac{G m}{8 a^{3}}}$
$\sqrt{\frac{G m}{4 a^{3}}}$

Solution

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