Question
Let $S=\left\{z \in \mathbb{C}: \bar{z}=i\left(z^{2}+\operatorname{Re}(\bar{z})\right)\right\}$. Then $\sum_\limits{z \in \mathrm{S}}|z|^{2}$ is equal to :
Let $S=\left\{z \in \mathbb{C}: \bar{z}=i\left(z^{2}+\operatorname{Re}(\bar{z})\right)\right\}$. Then $\sum_\limits{z \in \mathrm{S}}|z|^{2}$ is equal to :