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Question

$\int_\limits{0}^{\infty} \frac{6}{e^{3 x}+6 e^{2 x}+11 e^{x}+6} d x=$

$\log _{e}\left(\frac{256}{81}\right)$
$\log _{e}\left(\frac{64}{27}\right)$
$\log _{e}\left(\frac{32}{27}\right)$
$\log _{e}\left(\frac{512}{81}\right)$

Solution

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