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Question

Let $s_{1}, s_{2}, s_{3}, \ldots, s_{10}$ respectively be the sum to 12 terms of 10 A.P. s whose first terms are $1,2,3, \ldots .10$ and the common differences are $1,3,5, \ldots \ldots, 19$ respectively. Then $\sum_\limits{i=1}^{10} s_{i}$ is equal to :

7360
7220
7260
7380

Solution

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