Question
For $x \in \mathbb{R}$, two real valued functions $f(x)$ and $g(x)$ are such that, $g(x)=\sqrt{x}+1$ and $f \circ g(x)=x+3-\sqrt{x}$. Then $f(0)$ is equal to
For $x \in \mathbb{R}$, two real valued functions $f(x)$ and $g(x)$ are such that, $g(x)=\sqrt{x}+1$ and $f \circ g(x)=x+3-\sqrt{x}$. Then $f(0)$ is equal to