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Question

$\left|\begin{array}{ccc}x+1 & x & x \\ x & x+\lambda & x \\ x & x & x+\lambda^{2}\end{array}\right|=\frac{9}{8}(103 x+81)$, then $\lambda, \frac{\lambda}{3}$ are the roots of the equation :

$4 x^{2}+24 x-27=0$
$4 x^{2}-24 x+27=0$
$4 x^{2}-24 x-27=0$
$4 x^{2}+24 x+27=0$

Solution

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