On a temperature scale '$\mathrm{X}$', the boiling point of water is $65^{\circ} \mathrm{X}$ and the freezing point is $-15^{\circ} \mathrm{X}$. Assume that the $\mathrm{X}$ scale is linear. The equivalent temperature corresponding to $-95^{\circ} \mathrm{X}$ on the Farenheit scale would be:

Question

$-148^{\circ} \mathrm{F}$

$-48^{\circ} \mathrm{F}$

$-63^{\circ} \mathrm{F}$

$-112^{\circ} \mathrm{F}$

Solution

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