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Question

Let $\mu$ be the mean and $\sigma$ be the standard deviation of the distribution

${x_i}$ 0 1 2 3 4 5
${f_i}$ $k + 2$ $2k$ ${k^2} - 1$ ${k^2} - 1$ ${k^2} + 1$ $k - 3$

where $\sum f_{i}=62$. If $[x]$ denotes the greatest integer $\leq x$, then $\left[\mu^{2}+\sigma^{2}\right]$ is equal to :

9
8
6
7

Solution

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