A person travels $x$ distance with velocity $v_{1}$ and then $x$ distance with velocity $v_{2}$ in the same direction. The average velocity of the person is $\mathrm{v}$, then the relation between $v, v_{1}$ and $v_{2}$ will be.

Question

$\mathbf{V}=\mathbf{V}_{1}+\mathbf{V}_{2}$

$V=\frac{v_{1}+V_{2}}{2}$

$\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}$

$\frac{2}{\mathrm{~V}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}$

Solution

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