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Question

The time period of a satellite, revolving above earth's surface at a height equal to $\mathrm{R}$ will be

(Given $g=\pi^{2} \mathrm{~m} / \mathrm{s}^{2}, \mathrm{R}=$ radius of earth)

$\sqrt{32 R}$
$\sqrt{4 \mathrm{R}}$
$\sqrt{8 R}$
$\sqrt{2 R}$

Solution

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