Your AI-Powered Personal Tutor
Question

If $I(x) = \int {{e^{{{\sin }^2}x}}(\cos x\sin 2x - \sin x)dx} $ and $I(0) = 1$, then $I\left( {{\pi \over 3}} \right)$ is equal to :

$ - {e^{{3 \over 4}}}$
$ - {1 \over 2}{e^{{3 \over 4}}}$
${e^{{3 \over 4}}}$
${1 \over 2}{e^{{3 \over 4}}}$

Solution

Please login to view the detailed solution steps...

Go to DASH