An arc PQ of a circle subtends a right angle at its centre O. The mid point of the arc PQ is R. If $\overrightarrow {OP} = \overrightarrow u ,\overrightarrow {OR} = \overrightarrow v $, and $\overrightarrow {OQ} = \alpha \overrightarrow u + \beta \overrightarrow v $, then $\alpha ,{\beta ^2}$ are the roots of the equation :

Question

${x^2} + x - 2 = 0$

$3{x^2} + 2x - 1 = 0$

$3{x^2} - 2x - 1 = 0$

${x^2} - x - 2 = 0$

Solution

Please login to view the detailed solution steps...

Go to DASH