Question
Let a, b, c be three distinct positive real numbers such that ${(2a)^{{{\log }_e}a}} = {(bc)^{{{\log }_e}b}}$ and ${b^{{{\log }_e}2}} = {a^{{{\log }_e}c}}$.
Then, 6a + 5bc is equal to ___________.
Correct Answer
8
Let a, b, c be three distinct positive real numbers such that ${(2a)^{{{\log }_e}a}} = {(bc)^{{{\log }_e}b}}$ and ${b^{{{\log }_e}2}} = {a^{{{\log }_e}c}}$.
Then, 6a + 5bc is equal to ___________.