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Question

The area of the quadrilateral $\mathrm{ABCD}$ with vertices $\mathrm{A}(2,1,1), \mathrm{B}(1,2,5), \mathrm{C}(-2,-3,5)$ and $\mathrm{D}(1,-6,-7)$ is equal to :

48
$8 \sqrt{38}$
54
$9 \sqrt{38}$

Solution

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