A hydraulic automobile lift is designed to lift vehicles of mass $5000 \mathrm{~kg}$. The area of cross section of the cylinder carrying the load is $250 \mathrm{~cm}^{2}$. The maximum pressure the smaller piston would have to bear is $\left[\right.$ Assume $\left.g=10 \mathrm{~m} / \mathrm{s}^{2}\right]$