The acceleration due to gravity at height $h$ above the earth if $h

Question

The acceleration due to gravity at height $h$ above the earth if $h << \mathrm{R}$ (Radius of earth) is given by

$g^{\prime}=g\left(1-\frac{2 h}{R}\right)$

$g^{\prime}=g\left(1-\frac{2 h^{2}}{R^{2}}\right)$

$g^{\prime}=g\left(1-\frac{h^{2}}{2 R^{2}}\right)$

$g^{\prime}=g\left(1-\frac{h}{2 R}\right)$

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