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Question

The width of fringe is $2 \mathrm{~mm}$ on the screen in a double slits experiment for the light of wavelength of $400 \mathrm{~nm}$. The width of the fringe for the light of wavelength 600 $\mathrm{nm}$ will be:

4 mm
1.33 mm
2 mm
3 mm

Solution

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