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Question

The shortest distance between the lines $\frac{x-4}{4}=\frac{y+2}{5}=\frac{z+3}{3}$ and $\frac{x-1}{3}=\frac{y-3}{4}=\frac{z-4}{2}$ is :

$3 \sqrt{6}$
$6 \sqrt{2}$
$6 \sqrt{3}$
$2 \sqrt{6}$

Solution

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