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Question

In this figure the resistance of the coil of galvanometer G is $2 ~\Omega$. The emf of the cell is $4 \mathrm{~V}$. The ratio of potential difference across $\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ is:

$\frac{5}{4}$
$\frac{3}{4}$
1
$\frac{4}{5}$

Solution

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