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Question

If the radius of the first orbit of hydrogen atom is $\alpha_{0}$, then de Broglie's wavelength of electron in $3^{\text {rd }}$ orbit is :

$\frac{\pi \alpha^{3}}{6}$
$3\pi\alpha_0$
$6\pi\alpha_0$
$\frac{\pi \alpha^{3}}{3}$

Solution

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