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Question

The temperature of an ideal gas is increased from $200 \mathrm{~K}$ to $800 \mathrm{~K}$. If r.m.s. speed of gas at $200 \mathrm{~K}$ is $v_{0}$. Then, r.m.s. speed of the gas at $800 \mathrm{~K}$ will be:

$v_{0}$
$2 v_{0}$
$4 v_{0}$
$\frac{v_{0}}{4}$

Solution

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