Your AI-Powered Personal Tutor
Question

A capacitor of capacitance $150.0 ~\mu \mathrm{F}$ is connected to an alternating source of emf given by $\mathrm{E}=36 \sin (120 \pi \mathrm{t}) \mathrm{V}$. The maximum value of current in the circuit is approximately equal to :

$\frac{1}{\sqrt{2}} A$
$2 \sqrt{2} A$
$\sqrt{2} A$
$2 A$

Solution

Please login to view the detailed solution steps...

Go to DASH