$1 \times 10^{-5} ~\mathrm{M} ~\mathrm{AgNO}_{3}$ is added to $1 \mathrm{~L}$ of saturated solution of $\mathrm{AgBr}$. The conductivity of this solution at $298 \mathrm{~K}$ is _____________ $\times 10^{-8} \mathrm{~S} \mathrm{~m}^{-1}$.

[Given : $\mathrm{K}_{\mathrm{SP}}(\mathrm{AgBr})=4.9 \times 10^{-13}$ at $298 \mathrm{~K}$

$$ \begin{aligned} & \lambda_{\mathrm{Ag}^{+}}^{0}=6 \times 10^{-3} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1} \\ & \lambda_{\mathrm{Br}^{-}}^{0}=8 \times 10^{-3} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1} \\ & \left.\lambda_{\mathrm{NO}_{3}^{-}}^{0}=7 \times 10^{-3} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1}\right] \end{aligned} $$