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Question

Two dice are thrown independently. Let $\mathrm{A}$ be the event that the number appeared on the $1^{\text {st }}$ die is less than the number appeared on the $2^{\text {nd }}$ die, $\mathrm{B}$ be the event that the number appeared on the $1^{\text {st }}$ die is even and that on the second die is odd, and $\mathrm{C}$ be the event that the number appeared on the $1^{\text {st }}$ die is odd and that on the $2^{\text {nd }}$ is even. Then :

A and B are mutually exclusive
the number of favourable cases of the events A, B and C are 15, 6 and 6 respectively
B and C are independent
the number of favourable cases of the event $(\mathrm{A\cup B)\cap C}$ is 6

Solution

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