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Question

An electron of a hydrogen like atom, having $Z=4$, jumps from $4^{\text {th }}$ energy state to $2^{\text {nd }}$ energy state. The energy released in this process, will be :

(Given Rch = $13.6~\mathrm{eV}$)

Where R = Rydberg constant

c = Speed of light in vacuum

h = Planck's constant

$10.5 ~\mathrm{eV}$
$40.8 ~\mathrm{eV}$
$13.6 ~\mathrm{eV}$
$3.4 ~\mathrm{eV}$

Solution

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