Nucleus A having $Z=17$ and equal number of protons and neutrons has $1.2 ~\mathrm{MeV}$ binding energy per nucleon. Another nucleus $\mathrm{B}$ of $Z=12$ has total 26 nucleons and $1.8 ~\mathrm{MeV}$ binding energy per nucleons. The difference of binding energy of $\mathrm{B}$ and $\mathrm{A}$ will be _____________ $\mathrm{MeV}$.

Question

Nucleus A having $Z=17$ and equal number of protons and neutrons has $1.2 ~\mathrm{MeV}$ binding energy per nucleon.

Another nucleus $\mathrm{B}$ of $Z=12$ has total 26 nucleons and $1.8 ~\mathrm{MeV}$ binding energy per nucleons.

The difference of binding energy of $\mathrm{B}$ and $\mathrm{A}$ will be _____________ $\mathrm{MeV}$.

Correct Answer

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