A solution of $\mathrm{FeCl_3}$ when treated with $\mathrm{K_4[Fe(CN)_6]}$ gives a prussium blue precipitate due to the formation of :

Question

$\mathrm{Fe[Fe(CN)_{6}]}$

$\mathrm{Fe_{4}[Fe(CN)_{6}]_{3}}$

$\mathrm{Fe_{3}[Fe(CN)_{6}]_{2}}$

$\mathrm{K[Fe_{2}(CN)_{6}]}$

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