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Question

At $25^{\circ} \mathrm{C}$, the enthalpy of the following processes are given :

$\mathrm{H_2(g)+O_2(g)}$ $\to$ $2\mathrm{OH(g)}$ $\mathrm{\Delta H^\circ=78~kJ~mol^{-1}}$
$\mathrm{H_2(g)+\frac{1}{2}O_2(g)}$ $\to$ $\mathrm{H_2O(g)}$ $\mathrm{\Delta H^\circ=-242~kJ~mol^{-1}}$
$\mathrm{H_2(g)}$ $\to$ $\mathrm{2H(g)}$ $\mathrm{\Delta H^\circ=436~kJ~mol^{-1}}$
$\frac{1}{2}\mathrm{O_2(g)}$ $\to$ $\mathrm{O(g)}$ $\mathrm{\Delta H^\circ=249~kJ~mol^{-1}}$

What would be the value of X for the following reaction ? _____________ (Nearest integer)

$\mathrm{H_2O(g)\to H(g)+OH(g)~\Delta H^\circ=X~kJ~mol^{-1}}$

Correct Answer
499

Solution

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