The shortest distance between the lines ${{x - 5} \over 1} = {{y - 2} \over 2} = {{z - 4} \over { - 3}}$ and ${{x + 3} \over 1} = {{y + 5} \over 4} = {{z - 1} \over { - 5}}$ is :

Question

The shortest distance between the lines

${{x - 5} \over 1} = {{y - 2} \over 2} = {{z - 4} \over { - 3}}$ and

${{x + 3} \over 1} = {{y + 5} \over 4} = {{z - 1} \over { - 5}}$ is :

$7\sqrt 3 $