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Question

If earth has a mass nine times and radius twice to that of a planet P. Then $\frac{v_{e}}{3} \sqrt{x} \mathrm{~ms}^{-1}$ will be the minimum velocity required by a rocket to pull out of gravitational force of $\mathrm{P}$, where $v_{e}$ is escape velocity on earth. The value of $x$ is

1
3
2
18

Solution

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