Arrange the following orbitals in decreasing order of energy. A. $\mathrm{n}=3, \mathrm{l}=0, \mathrm{~m}=0$ B. $\mathrm{n}=4, \mathrm{l}=0, \mathrm{~m}=0$ C. $\mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}=0$ D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}=1$ The correct option for the order is :

Question

Arrange the following orbitals in decreasing order of energy.

A. $\mathrm{n}=3, \mathrm{l}=0, \mathrm{~m}=0$

B. $\mathrm{n}=4, \mathrm{l}=0, \mathrm{~m}=0$

C. $\mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}=0$

D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}=1$

The correct option for the order is :

$\mathrm{B}>\mathrm{D}>\mathrm{C}>\mathrm{A}$

$\mathrm{A}>\mathrm{C}>\mathrm{B}>\mathrm{D}$

$\mathrm{D}>\mathrm{B}>\mathrm{A}>\mathrm{C}$

$\mathrm{D}>\mathrm{B}>\mathrm{C}>\mathrm{A}$

Solution

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