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Question

The correct order of basicity of oxides of vanadium is :

$\mathrm{V_2O_3 > V_2O_5 > V_2O_4}$
$\mathrm{V_2O_3 > V_2O_4 > V_2O_5}$
$\mathrm{V_2O_5 > V_2O_4 > V_2O_3}$
$\mathrm{V_2O_4 > V_2O_3 > V_2O_5}$

Solution

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