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Question

The initial speed of a projectile fired from ground is $\mathrm{u}$. At the highest point during its motion, the speed of projectile is $\frac{\sqrt{3}}{2} u$. The time of flight of the projectile is :

$\frac{u}{g}$
$\frac{2u}{g}$
$\frac{u}{2g}$
$\frac{\sqrt3u}{g}$

Solution

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