A point source of $100 \mathrm{~W}$ emits light with $5 \%$ efficiency. At a distance of $5 \mathrm{~m}$ from the source, the intensity produced by the electric field component is:
$\frac{1}{40 \pi} \frac{W}{m^2}$
$\frac{1}{10 \pi} \frac{W}{m^2}$
$\frac{1}{20 \pi} \frac{W}{m^2}$
$\frac{1}{2 \pi} \frac{W}{m^2}$
Solution
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