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Question

A small object at rest, absorbs a light pulse of power $20 \mathrm{~mW}$ and duration $300 \mathrm{~ns}$. Assuming speed of light as $3 \times 10^{8} \mathrm{~m} / \mathrm{s}$, the momentum of the object becomes equal to :

$1 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
$0.5 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
$3 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
$2 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

Solution

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