Speed of an electron in Bohr's $7^{\text {th }}$ orbit for Hydrogen atom is $3.6 \times 10^{6} \mathrm{~m} / \mathrm{s}$. The corresponding speed of the electron in $3^{\text {rd }}$ orbit, in $\mathrm{m} / \mathrm{s}$ is :

Question

$\left(1.8 \times 10^{6}\right)$

$\left(7.5 \times 10^{6}\right)$

$\left(8.4 \times 10^{6}\right)$

$\left(3.6 \times 10^{6}\right)$

Solution

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