Your AI-Powered Personal Tutor
Question

In a series LR circuit with $\mathrm{X_L=R}$, power factor P1. If a capacitor of capacitance C with $\mathrm{X_C=X_L}$ is added to the circuit the power factor becomes P2. The ratio of P1 to P2 will be :

1 : $\sqrt2$
1 : 3
1 : 2
1 : 1

Solution

Please login to view the detailed solution steps...

Go to DASH