Question
Let $y=y(x)$ be the solution of the differential equation $x{\log _e}x{{dy} \over {dx}} + y = {x^2}{\log _e}x,(x > 1)$. If $y(2) = 2$, then $y(e)$ is equal to
Let $y=y(x)$ be the solution of the differential equation $x{\log _e}x{{dy} \over {dx}} + y = {x^2}{\log _e}x,(x > 1)$. If $y(2) = 2$, then $y(e)$ is equal to