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Question

The area of the region $A = \left\{ {(x,y):\left| {\cos x - \sin x} \right| \le y \le \sin x,0 \le x \le {\pi \over 2}} \right\}$ is

$\sqrt 5 + 2\sqrt 2 - 4.5$
$1 - {3 \over {\sqrt 2 }} + {4 \over {\sqrt 5 }}$
$\sqrt 5 - 2\sqrt 2 + 1$
${3 \over {\sqrt 5 }} - {3 \over {\sqrt 2 }} + 1$

Solution

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