The value of the integral $\int\limits_{1/2}^2 {{{{{\tan }^{ - 1}}x} \over x}dx} $ is equal to :

Question

${\pi \over 2}{\log _e}2$

${\pi \over 4}{\log _e}2$

${1 \over 2}{\log _e}2$

$\pi {\log _e}2$

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