The equation of a circle is given by $x^2+y^2=a^2$, where a is the radius. If the equation is modified to change the origin other than (0, 0), then find out the correct dimensions of A and B in a new equation : ${(x - At)^2} + {\left( {y - {t \over B}} \right)^2} = {a^2}$. The dimensions of t is given as $[\mathrm{T^{-1}]}$.

Question

$\mathrm{A=[L^{-1}T^{-1}],B=[LT^{-1}]}$

$\mathrm{A=[L^{-1}T^{-1}],B=[LT]}$

$\mathrm{A=[LT],B=[L^{-1}T^{-1}]}$

$\mathrm{A=[L^{-1}T],B=[LT^{-1}]}$

Solution

Please login to view the detailed solution steps...

Go to DASH