An object moves at a constant speed along a circular path in a horizontal plane with center at the origin. When the object is at $x=+2~\mathrm{m}$, its velocity is $\mathrm{ - 4\widehat j}$ m/s. The object's velocity (v) and acceleration (a) at $x=-2~\mathrm{m}$ will be

Question

$v=4\mathrm{\widehat i~m/s},a=8\mathrm{\widehat j~m/s^2}$

$v=4\mathrm{\widehat j~m/s},a=8\mathrm{\widehat i~m/s^2}$

$v=-4\mathrm{\widehat i~m/s},a=-8\mathrm{\widehat j~m/s^2}$

$v=-4\mathrm{\widehat j~m/s},a=8\mathrm{\widehat i~m/s^2}$

Solution

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